Question

How to calculate the series (1^1) + (2^2) + (3^3) + (4^4) + ... + (N^N) in Node.js

Answer 1

const N = 6;
let sum = 0;
  
for (let i = 1; i <= N; i++) {
     let pw = Math.pow(i, i);
     console.log(pw + " + ");
     sum = sum + pw;
}
  
console.log(" = " + sum);
 
   
   
   
   
/*
run:
   
1 + 
4 + 
27 + 
256 + 
3125 + 
46656 + 
 = 50069
   
*/

 

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