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How to calculate the series (1^1) + (2^2) + (3^3) + (4^4) + ... + (N^N) in Python



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asked Mar 28, 2022 by avibootz
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1 Answer

0 votes 
N = 4
sum = 0
  
for i in range(1, N + 1):
    pw = pow(i, i)
    sum = sum + pw
    print(pw, " + ")
    
print(" = ", sum)    



'''
run:

1  + 
4  + 
27  + 
256  + 
 =  288
 
'''

 



answered Mar 28, 2022 by avibootz

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