Question

How to calculate the series (1^1) + (2^2) + (3^3) + (4^4) + ... + (N^N) in C++

Answer 1

#include <iostream>
#include <cmath>

int main() {
    int N = 4, sum = 0;
 
    for (int i = 1; i <= N; i++) {
        int pw = pow(i, i);
        std::cout << pw << " + ";
        sum = sum + pw;
    }
 
    std::cout << " = " << sum;
}


 
 
/*
run:
 
1 + 4 + 27 + 256 +  = 288
 
*/

 

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