Question

How to check whether a given number is a disarium number in JavaScript

Answer 1

// 1^1 + 7^2 + 5^3 = 1 + 49 + 125 = 175
 
const num = 175;
let len = Math.trunc(Math.log10(num)) + 1;
let sum = 0;
    
let temp = num;
while (temp > 0) {
    let remainder = temp % 10;
    sum = sum + Math.pow(remainder, len);
    temp = Math.trunc(temp / 10);
    len--;
}
    
if (num == sum)
    console.log(num + " is a disarium number");
else
    console.log(num + " is not a disarium number");
   
    
    
    
    
    
/*
run:
    
"175 is a disarium number"
    
*/

 

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