Question

How to check whether a given number is a disarium number in PHP

Answer 1

// 1^1 + 3^2 + 5^3 = 1 + 9 + 125 = 135

$num = 135;
$remainder = 0;
$len = (int)log10($num) + 1;
$sum = 0;
 
$temp = $num;
while ($temp > 0) {
    $remainder = $temp % 10;
    $sum = $sum + pow($remainder, $len);
    $temp = (int)($temp / 10);
    $len--;
}
  
if ($num == (int)$sum)
    echo $num . " is a disarium number";
else
    echo $num . " is not a disarium number";
 
  
  
  
/*
run:
  
135 is a disarium number
  
*/

 

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