Question

How to get the 3 smallest values from array in JavaScript

Answer 1

const arr = [ 12, 98, 80, 50, 88, 35, 70, 60, 97, 85, 89 ];
 
arr.sort((a, b) => a < b ? -1 : a > b ? 1 : 0);
   
console.log(arr[0] + " " + arr[1] + " " + arr[2]);  
 
const smallest3 = arr.slice(0, 3) 
console.log(smallest3);
 
   
     
     
/*
run:
     
"12 35 50"
[12, 35, 50]
     
*/

 

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