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How to get the 3 smallest values from a list in Python

2 Answers

0 votes
lst = [12, 98, 80, 50, 88, 35, 70, 60, 97, 85, 89]

smallest3 = sorted(zip(lst))[:3]

print(smallest3[0][0])
print(smallest3[1][0])
print(smallest3[2][0])




'''
run:

12
35
50

'''

 



answered Jun 10, 2021 by avibootz
0 votes
from heapq import nsmallest

lst = [12, 98, 80, 50, 88, 35, 70, 60, 97, 85, 89]

smallest3 = nsmallest(3, lst)

print(smallest3[0])
print(smallest3[1])
print(smallest3[2])




'''
run:

12
35
50

'''

 



answered Jun 10, 2021 by avibootz

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