How to print the 3 smallest values from array in C#

1 Answer

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using System;
 
class Program
{
    static void printSmallest3(int[] arr) {
        int first, second, third;
        int len = arr.Length;
  
        if (len < 3) {
            return;
        }
  
        first = third = second = int.MaxValue;
 
        for (int i = 0; i < len; i++) {
            if (arr[i] < first) {
                third = second;
                second = first;
                first = arr[i];
            }
  
            else if (arr[i] < second) {
                third = second;
                second = arr[i];
            }
  
            else if (arr[i] < third)
                third = arr[i];
        }
  
        Console.WriteLine(first + " " + second + " " + third);
    }
    static void Main() {
        int[] arr = new int[] { 12, 98, 80, 50, 88, 35, 70, 60, 97, 85, 89 };
 
        printSmallest3(arr);
    }
}
 
 
 
 
/*
run:
 
12 35 50
 
*/

 



answered Jun 9, 2021 by avibootz

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