How to print the 3 smallest values from array in C

1 Answer

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#include <stdio.h>
#include <limits.h> 
 
void printSmallest3(int arr[], int size) {
    int first, second, third;
  
    if (size < 3) {
        return;
    }
  
    third = first = second = INT_MAX;
    for (int i = 0; i < size; i++) {
        if (arr[i] < first) {
            third = second;
            second = first;
            first = arr[i];
        }
        else if (arr[i] < second) {
            third = second;
            second = arr[i];
        }
        else if (arr[i] < third)
            third = arr[i];
    }
    printf("%d %d %d\n", first, second, third);
}
  
 
int main()
{
    int arr[] = { 98, 12, 80, 50, 88, 35, 60, 97, 85, 89 };
    int size = sizeof(arr) / sizeof(arr[0]);
     
    printSmallest3(arr, size);
     
    return 0;
}
 
 
 
 
/*
run:
 
12 35 50
 
*/

 



answered Jun 8, 2021 by avibootz

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