Question

How to generate binary numbers from 1 to N in Java

Answer 1

public class MyClass {
    public static final int LEN = 100;
    static void printBinaryNumber(int n) {
        int binary[] = new int[LEN];
        int i = 0;
          
        while (n > 0) {
            binary[i] = n % 2;
            n = n / 2;
            i++;
        }
        for (int j = i - 1; j >= 0; j--)
            System.out.print(binary[j]);
        System.out.println();
    }
    static void generateBinaryNumbers(int n) {
        for (int i = 1; i <= n; i++) {
            printBinaryNumber(i);
        }
    }
    public static void main(String args[]) {
        int N = 15;
 
        generateBinaryNumbers(N);
    }
}



/*
run:

1
10
11
100
101
110
111
1000
1001
1010
1011
1100
1101
1110
1111

*/

 

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Answer 2

import java.util.ArrayDeque;
import java.util.Queue;

public class MyClass {
    static void printBinaryNumbers(int n) {
    	Queue<String> q = new ArrayDeque<>();
		q.add("1");

		int i = 1;
		while (i++ <= n) {
			q.add(q.peek() + '0');
			q.add(q.peek() + '1');

			System.out.print(q.poll() + '\n');
		}
    }
    public static void main(String args[]) {
        int N = 15;
  
        printBinaryNumbers(N);
    }
}
 
 
 
/*
run:
 
1
10
11
100
101
110
111
1000
1001
1010
1011
1100
1101
1110
1111
 
*/

 

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Answer 3

public class MyClass {
    static void generateBinaryNumbers(int n) {
        for (int i = 1; i <= n; i++) {
            System.out.println(Integer.toBinaryString(i));
        }
    }
    public static void main(String args[]) {
        int N = 15;
  
        generateBinaryNumbers(N);
    }
}
 
 
 
/*
run:
 
1
10
11
100
101
110
111
1000
1001
1010
1011
1100
1101
1110
1111
 
*/

 

70+ SQL courses for beginners and professionals