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How to generate binary numbers from 1 to N in C#

2 Answers

0 votes
using System;

class Program
{
    static int LEN = 100;
    static void printBinaryNumber(int n) {
        int[] binary = new int[LEN];
        int i = 0;
           
        while (n > 0) {
            binary[i] = n % 2;
            n = n / 2;
            i++;
        }
        for (int j = i - 1; j >= 0; j--)
            Console.Write(binary[j]);
        Console.WriteLine();
    }
    static void generateBinaryNumbers(int n) {
        for (int i = 1; i <= n; i++) {
            printBinaryNumber(i);
        }
    }
    static void Main() {
        int N = 15;
  
        generateBinaryNumbers(N);
    }
}



/*
run:

1
10
11
100
101
110
111
1000
1001
1010
1011
1100
1101
1110
1111

*/

 



answered Jul 23, 2020 by avibootz
0 votes
using System;
 
class Program
{
    static void generateBinaryNumbers(int n) {
        for (int i = 1; i <= n; i++) {
            Console.WriteLine(Convert.ToString(i, 2));
        }
    }
    static void Main() {
        int N = 15;
   
        generateBinaryNumbers(N);
    }
}
 
 
 
/*
run:
 
1
10
11
100
101
110
111
1000
1001
1010
1011
1100
1101
1110
1111
 
*/

 



answered Jul 23, 2020 by avibootz

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