Question

How to sort a dictionary by keys in Python

Answer 1

import collections

d = {'python': 5, 'php': 3, 'java': 9, 'c++': 1}
   
od = collections.OrderedDict(sorted(d.items(), key=lambda k: k[0]))
print(od)

d = dict(od)  
print(d)
  
  
  
'''
run:
   
OrderedDict([('c++', 1), ('java', 9), ('php', 3), ('python', 5)])
{'c++': 1, 'java': 9, 'php': 3, 'python': 5}
 
'''

 

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Answer 2

import collections

dict = {'python': 5, 'php': 3, 'java': 9, 'c++': 1}
   
od = collections.OrderedDict(sorted(dict.items(), key=lambda k: k[0]))
  
for key, value in od.items(): 
    print(key, value) 
  
  
  
'''
run:
   
c++ 1
java 9
php 3
python 5
 
'''

 

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Answer 3

dict = {'python': 5, 'php': 3, 'java': 9, 'c++': 1}
  
dict = sorted(dict.items())

print(dict)
 
 
 
'''
run:
  
[('c++', 1), ('java', 9), ('php', 3), ('python', 5)]

'''

 

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Answer 4

d = {'python': 5, 'php': 3, 'java': 9, 'c++': 1}
   
d = dict(sorted(d.items()))
 
print(d)
  
  
  
'''
run:
   
{'c++': 1, 'java': 9, 'php': 3, 'python': 5}

'''

 

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