Question

How to sort a dictionary by key in ascending order Python

Answer 1

dictionary = {'D': 5, 'F': 6, 'A': 3, 'E': 8, 'C': 1, "B": 7}
   
dic_sort_by_value = dict(sorted(dictionary.items(), key=lambda item: item[0]))
  
print(dic_sort_by_value)
 
 
 
'''
run:

{'A': 3, 'B': 7, 'C': 1, 'D': 5, 'E': 8, 'F': 6}
 
'''

 

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Answer 2

dic = {'php': 99, 'c': 108, 'c++': 31, 'python': 21}

dic = dict(sorted(dic.items()))

for key, value in dic.items():
    print(f"{key} - {value}")



'''
run:

c - 108
c++ - 31
php - 99
python - 21

'''

 

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