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How to pass a function as a parameter in C

1 Answer

0 votes
#include <stdio.h>
  
void function(int n) {
	printf("n = %d\n", n);
}

void show( void (*f)(int) ) {
	for (int i = 0; i < 10; i++) {
		(*f)(i);
  }
}

int main ()
{
	show(function);
	
	return 0;
}




/*
run:

n = 0
n = 1
n = 2
n = 3
n = 4
n = 5
n = 6
n = 7
n = 8
n = 9

*/

 



answered Feb 1, 2020 by avibootz
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