Question

How to pass a function as a parameter in C++

Answer 1

#include <iostream>
 
using namespace std;
 
typedef void (*function_pointer)(int args);
 
void f(int n, function_pointer show) {
   show(n);
}
 
void show(int n) {
   cout << n;
}
 
 
int main() {
   f(100, (function_pointer)show);
     
   return 0;
}
 
 
 
 
/*
run:
 
100
 
*/

 

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Answer 2

#include <iostream>
 
using namespace std;
 
void f(int n, void (*function_pointer)(int)) {
   function_pointer(n);
}
 
void show(int n) {
   cout << n;
}
 
 
int main() {
   f(100, show);
     
   return 0;
}
 
 
 
 
/*
run:
 
100
 
*/

 

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