Question

How to check if a number is perfect square in Python

Answer 1

import math

def is_perfect_square(n):
   sq = math.sqrt(n)
   
   return ((sq - math.floor(sq)) == 0)


if (is_perfect_square(36)): 
    print("Yes"); 
else:
    print("No"); 
         
if (is_perfect_square(20)):
    print("Yes"); 
else:
    print("No"); 
    
    
    
'''
run:

Yes
No

'''

 

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