Question

How to check if a number is a perfect square in Go

Answer 1

// Perfect squares are: 1(1*1), 4(2*2), 9(3*3), 16(4*4), 25(5*5), 36(6*6)...

package main

import (
	"fmt"
	"math"
)

func isPerfectSquare(n float64) bool {
	sqr := math.Sqrt(n)
	
	return sqr == math.Floor(sqr)
}

func main() {
	if isPerfectSquare(36) {
		fmt.Println("Yes")
	} else {
		fmt.Println("No")
	}

	if isPerfectSquare(20) {
		fmt.Println("Yes")
	} else {
		fmt.Println("No")
	}
}



/*
run:

Yes
No

*/

 

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