Question

How to initialize two base classes from derived class in C++

Answer 1

#include <iostream>

using std::cout;
using std::endl;

class Base1 {
protected:
	int a;
public:
	Base1(int _a) {
		a = _a;
		cout << "class Base1: " << a << endl;
	}
	~Base1() {
		cout << "~Base1()" << endl;
	}
};

class Base2 {
protected:
	int b;
public:
	Base2(int _b) {
		b = _b;
		cout << "class Base2: " << b << endl;
	}
	~Base2() {
		cout << "~Base2()" << endl;
	}
};

class Derived : public Base1, public Base2 {
public:
	Derived(int _a, int _b) : Base1(_a), Base2(_b) {
		cout << "Constructor Derived" << endl;
	}

	~Derived() {
		cout << "Destructor Derived" << endl;
	}
	void print() {
		cout << "Derived: " << a << " " << b << endl;
	}
};

int main()
{
	Derived o(17, 13);

	o.print();

	return 0;
}

/*
run:

class Base1: 17
class Base2: 13
Constructor Derived
Derived: 17 13
Destructor Derived
~Base2()
~Base1()

*/

 

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