Question

How to use dynamic_cast between base class and derived class in C++

Answer 1

#include <iostream>
#include <exception>

using std::cout;
using std::endl;

class Base { 
	virtual void method() { 
		cout << "class Base" << endl; 
	} 
};
class Derived : public Base { 
	virtual void method() {
		cout << "class Derived" << endl;
	}
};

int main() 
{
	try 
	{
		Base *pb = new Derived;
		Derived *pd;

		pd = dynamic_cast<Derived*>(pb);
		
		cout << pb << endl;
		cout << pd << endl;
	}
	catch (std::exception &e) { 
		cout << "Exception: " << e.what();
	}

	return 0;
}


/*
run:

00736038
00736038

*/

 

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Answer 2

#include <iostream>
#include <exception>

using std::cout;
using std::endl;

class Base { 
	virtual void method() { 
		cout << "class Base" << endl; 
	} 
};
class Derived : public Base { 
	virtual void method() {
		cout << "class Derived" << endl;
	}
};

int main() 
{
	try 
	{
		Base *pb = new Base;
		Derived *pd;

		pd = dynamic_cast<Derived*>(pb);
		
		cout << pb << endl;
		cout << pd << endl;
	}
	catch (std::exception &e) { 
		cout << "Exception: " << e.what();
	}

	return 0;
}


/*
run:

00386038
00000000

*/

 

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