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How to build sparse array in Swift

1 Answer

0 votes
import Foundation

/*
    A sparse array stores only non‑zero values.
    Swift's Dictionary<Int, Int> is a natural fit:
      - Keys represent indices that actually exist
      - Values represent stored data
      - Lookup and insertion are fast
*/

typealias SparseArray = [Int: Int]
typealias DenseArray  = [Int]

/*
    buildDense:
    Converts sparse → dense.

    Steps:
    1. Find the maximum index in the sparse structure
    2. Allocate a dense array of size maxIndex + 1
    3. Fill with zeros
    4. Copy sparse values into their positions
*/
func buildDense(_ sa: SparseArray) -> DenseArray {
    // Find largest index
    let maxIndex: Int = sa.keys.max() ?? 0

    // Allocate dense array filled with zeros
    var dense: DenseArray = Array(repeating: 0, count: maxIndex + 1)

    // Copy sparse values
    for (index, value) in sa {
        dense[index] = value
    }

    return dense
}

func main() {
    // Sparse entries (zero values omitted)
    let sa: SparseArray = [
        2: 10,
        10: 7,
        8: 42,
        3: 5
    ]

    let dense: DenseArray = buildDense(sa)

    print("Dense array:")
    print("[ ", terminator: "")
    dense.forEach { value in print("\(value) ", terminator: "") }
    print("]")
}

main()


/*
run:

Dense array:
[ 0 0 10 5 0 0 0 0 42 0 7 ]

*/

 



answered 2 days ago by avibootz
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