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How to build sparse array in JavaScript

1 Answer

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/*
    A sparse array stores only non‑zero values.
    JavaScript's Map is a natural fit:
      - Keys represent indices that actually exist
      - Values represent stored data
      - Lookup and insertion are fast
*/

/*
    buildDense:
    Converts sparse → dense.

    Steps:
    1. Find the maximum index in the sparse structure
    2. Allocate a dense list of size maxIndex + 1
    3. Fill with zeros
    4. Copy sparse values into their positions
*/
function buildDense(sparse) {
    let maxIndex = 0;

    // Find largest index
    for (const [index] of sparse) {
        if (index > maxIndex) {
            maxIndex = index;
        }
    }

    // Allocate dense list filled with zeros
    const dense = Array(maxIndex + 1).fill(0);

    // Copy sparse values
    for (const [index, value] of sparse) {
        dense[index] = value;
    }

    return dense;
}

function main() {
    // Sparse entries (zero values omitted)
    const sparse = new Map([
        [2, 10],
        [10, 7],
        [8, 42],
        [3, 5]
    ]);

    const dense = buildDense(sparse);

    console.log("Dense array:");
    console.log("[", ...dense, "]");
}

main();



/*
run:

Dense array:
[ 0 0 10 5 0 0 0 0 42 0 7 ]

*/

 



answered 2 days ago by avibootz
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