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How to find the Nth set bit in a 64‑bit integer with C++

1 Answer

0 votes
#include <iostream>
#include <cstdint>
#include <bitset>
  
/*
    findNthSetBit:
    ---------------
    Given:
        - x : a 64-bit integer
        - n : which set bit to find (1-based index)
  
    Returns:
        A 64-bit mask with ONLY the Nth set bit of x turned on.
        If n is larger than the number of set bits, returns 0.
  
    Algorithm:
        - Repeatedly locate the lowest set bit using std::countr_zero.
        - Remove that bit using x &= (x - 1).
        - When we reach the Nth one, return a mask with that bit set.
*/
std::uint64_t findNthSetBit(std::uint64_t x, unsigned n)
{
    while (x != 0) {
        // Find index of lowest set bit (0–63)
        unsigned index = std::countr_zero(x);
  
        // If this is the Nth set bit, return a mask with only that bit set
        if (--n == 0)
            return 1ULL << index;
  
        // Remove the lowest set bit
        x &= (x - 1);
    }
  
    // If we run out of bits before reaching n, return 0
    return 0;
}
  
int main()
{
    std::uint64_t value =
        0b0000000000000000000010000000000000001101001101101100100010100000ULL;
  
    unsigned n = 4; // Find the 4th set bit
  
    std::uint64_t result = findNthSetBit(value, n);
  
    std::cout << "Input value:  " << std::bitset<64>(value) << "\n";
    std::cout << "N = " << n << "\n";
    std::cout << "Result mask:  " << std::bitset<64>(result) << "\n";
  
    std::cout << "\n";
}
  
  
/*
run:
  
Input value:  0000000000000000000010000000000000001101001101101100100010100000
N = 4
Result mask:  0000000000000000000000000000000000000000000000000100000000000000
  
*/

 



answered Jul 24 by avibootz
edited Jul 25 by avibootz
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