/*
roundUp(n, multiple)
--------------------
Rounds the integer n *up* to the nearest multiple of `multiple`.
Mathematically:
result = ceil(n / multiple) * multiple
We use integer arithmetic for efficiency:
(n + multiple - 1) / multiple → smallest integer ≥ n/m
*/
def roundUp(n: Int, multiple: Int): Int = {
if (multiple <= 0) {
// Defensive programming: avoid undefined behavior.
// In real-world code, you'd throw or handle this differently.
n
} else {
// Efficient integer rounding up:
((n + multiple - 1) / multiple) * multiple
}
}
@main def main(): Unit = {
println(s"roundUp(53, 20) = ${roundUp(53, 20)}")
println(s"roundUp(68, 30) = ${roundUp(68, 30)}")
println(s"roundUp(7, 100) = ${roundUp(7, 100)}")
println(s"roundUp(119, 100) = ${roundUp(119, 100)}")
println(s"roundUp(781, 100) = ${roundUp(781, 100)}")
println(s"roundUp(1026, 100) = ${roundUp(1026, 100)}")
println(s"roundUp(11689, 1000) = ${roundUp(11689, 1000)}")
}
/*
run:
roundUp(53, 20) = 60
roundUp(68, 30) = 90
roundUp(7, 100) = 100
roundUp(119, 100) = 200
roundUp(781, 100) = 800
roundUp(1026, 100) = 1100
roundUp(11689, 1000) = 12000
*/
