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How to find the minimal possible sum of two distinct elements in an array with Ruby

1 Answer

0 votes
#
#    Goal:
#    -----
#    Find the minimal value of (a[i] + a[j]) for any two distinct elements in an array.
#
#    Efficient Strategy (O(n)):
#    --------------------------
#    The smallest possible sum of two distinct elements is obtained by:
#        - finding the smallest element
#        - finding the second smallest element
#    Because any other pair must be >= one of these two.
#
#    We scan the array once, keeping track of:
#        - min1  = smallest element seen so far
#        - min2  = second smallest element seen so far
#

# A function that computes the minimal sum of two distinct elements.
def minimal_two_sum(arr)
  # Handle edge case: need at least two elements
  if arr.length < 2
    raise ArgumentError, "Array must contain at least two elements."
  end

  # Initialize min1 and min2 to very large values
  min1 = Float::INFINITY
  min2 = Float::INFINITY

  # Single pass through the array
  arr.each do |x|
    if x < min1
      # x becomes the new smallest; old min1 becomes min2
      min2 = min1
      min1 = x
    elsif x < min2
      # x is not the smallest, but smaller than the second smallest
      min2 = x
    end
  end

  # The minimal sum of two distinct elements
  min1 + min2
end


arr = [7, -3, 10, 1, 5, 2, 4]

begin
  result = minimal_two_sum(arr)
  puts "Minimal sum of two elements: #{result}"
rescue => e
  puts "Error: #{e.message}"
end


#
# run:
#
# Minimal sum of two elements: -2
#

 



answered Jul 21 by avibootz

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