How to split a 32‑bit integer into its four bytes in Scala

1 Answer

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/*
    split_bytes(n)
    --------------
    Splits a 32-bit unsigned integer into its four bytes.

    Layout (little-endian order):
        byte[0] = lowest  8 bits
        byte[1] = next     8 bits
        byte[2] = next     8 bits
        byte[3] = highest  8 bits

    Uses bitwise AND and shifts:
        n & 0xFF        → extract lowest byte
        (n >> 8) & 0xFF → extract next byte
        ...
*/

def split_bytes(n: Int): Array[Int] = {
    Array(
        n & 0xFF,              // lowest byte
        (n >> 8) & 0xFF,
        (n >> 16) & 0xFF,
        (n >> 24) & 0xFF       // highest byte
    )
}

/*
    print_bits(label, value)
    ------------------------
    Prints an 8-bit or 32-bit value in binary.

    Uses value.toBinaryString and manual zero-padding.
*/
def print_bits(label: String, value: Int, bits: Int): Unit = {
    val binary = {
        val raw = value.toBinaryString
        if (raw.length < bits)
            "0" * (bits - raw.length) + raw
        else raw
    }

    println(s"$label ($bits bits): $binary")
}

@main def main(): Unit = {
    val value: Int = 3298312

    val bytes: Array[Int] = split_bytes(value)

    println("Bytes (little-endian order):")
    for (i <- bytes.indices) {
        println(s"byte[$i]: ${bytes(i)}")
    }

    println("\nBit representation:")

    // Print full 32-bit value
    print_bits("Full value", value, 32)

    // Print each byte in binary
    for (i <- bytes.indices) {
        print_bits(s"byte[$i]", bytes(i), 8)
    }
}


/*
run:

Bytes (little-endian order):
byte[0]: 8
byte[1]: 84
byte[2]: 50
byte[3]: 0

Bit representation:
Full value (32 bits): 00000000001100100101010000001000
byte[0] (8 bits): 00001000
byte[1] (8 bits): 01010100
byte[2] (8 bits): 00110010
byte[3] (8 bits): 00000000

*/

 



answered Jul 20 by avibootz
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