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How to determine whether two axis‑aligned rectangles overlap in C++

1 Answer

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#include <iostream>

/*
Axis‑aligned rectangles are simply rectangles whose edges are parallel to the 
coordinate axes — meaning their sides are horizontal and vertical. 
That single assumption makes the overlap test dramatically simpler and faster.
*/

/*
    Rectangle overlap detection (axis-aligned)

    Each rectangle is defined by:
        - x, y : coordinates of its top-left corner
        - w, h : width and height

    Two rectangles DO NOT overlap if any separating condition is true:
        - One is completely to the left of the other
        - One is completely to the right of the other
        - One is completely above the other
        - One is completely below the other

    Otherwise, they overlap.

    This is the standard O(1) test for axis-aligned rectangles.
*/

struct Rect {
    double x;      // top-left X
    double y;      // top-left Y
    double w;      // width
    double h;      // height
};

/*
    Returns true if rectangles A and B overlap.
*/
bool rectanglesOverlap(const Rect& A, const Rect& B) {
    // Compute edges of A
    double A_left   = A.x;
    double A_right  = A.x + A.w;
    double A_top    = A.y;
    double A_bottom = A.y + A.h;

    // Compute edges of B
    double B_left   = B.x;
    double B_right  = B.x + B.w;
    double B_top    = B.y;
    double B_bottom = B.y + B.h;

    // Separating conditions:
    if (A_right <= B_left)   return false;   // A is left of B
    if (B_right <= A_left)   return false;   // B is left of A
    if (A_bottom <= B_top)   return false;   // A is above B
    if (B_bottom <= A_top)   return false;   // B is above A

    return true; // Otherwise, they overlap
}

int main() {
    Rect A{10, 10, 30, 20};   // Example rectangle A
    Rect B{25, 15, 40, 25};   // Overlaps A
    Rect C{100, 100, 10, 10}; // Does not overlap A

    std::cout << "A vs B overlap? " << (rectanglesOverlap(A, B) ? "YES" : "NO") << "\n";
    std::cout << "A vs C overlap? " << (rectanglesOverlap(A, C) ? "YES" : "NO") << "\n";
}



/*
run:

A vs B overlap? YES
A vs C overlap? NO

*/

 



answered Jul 18 by avibootz

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