How to determine whether an n‑bit binary number is divisible by 5 in Kotlin

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// function to compute whether a binary number is divisible by 5
// it processes the bits left to right and keeps track of the remainder modulo 5
// for each bit b:
//     remainder = (remainder * 2 + b) % 5
fun isDivisibleByFive(bin: String): Boolean {

    // remainder modulo 5 while scanning bits
    var remainder: Int = 0

    // scan each bit of the binary number
    for (bit in bin) {

        // convert '0' or '1' to integer 0 or 1
        val b: Int = bit.code - '0'.code

        // update remainder using modulo arithmetic
        remainder = (remainder * 2 + b) % 5
    }

    // divisible if final remainder is zero
    return remainder == 0
}

fun main() {

    // read an n-bit binary number as a string
    val bin: String = "01000110"  // 70

    val divisible: Boolean = isDivisibleByFive(bin)

    println("Binary number: $bin")
    println("Divisible by 5: ${if (divisible) "yes" else "no"}")

    /*
      Example walk-through for bin = 01000110:

      Start: remainder = 0

      bit = 0 → remainder = (0*2 + 0) % 5 = 0
      bit = 1 → remainder = (0*2 + 1) % 5 = 1
      bit = 0 → remainder = (1*2 + 0) % 5 = 2
      bit = 0 → remainder = (2*2 + 0) % 5 = 4
      bit = 0 → remainder = (4*2 + 0) % 5 = 3
      bit = 1 → remainder = (3*2 + 1) % 5 = 2
      bit = 1 → remainder = (2*2 + 1) % 5 = 0
      bit = 0 → remainder = (0*2 + 0) % 5 = 0

      Final remainder = 0 → divisible by 5
    */
}


/*
run:

Binary number: 01000110
Divisible by 5: yes

*/

 



answered Jun 28 by avibootz

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