Question

How to calculate the values of a and b where a × b = 899 in C

Answer 1

#include <stdio.h>

// You can compute all integer pairs (a, b) such that a × b = 899 
// by checking every divisor of 899

void findAB(int n) {
    for (int a = 1; a <= n; a++) {
        if (n % a == 0) {
            int b = n / a;
            printf("a = %d, b = %d\n", a, b);
        }
    }
}

int main() {
    int n = 899;
    
    findAB(n);
    
    return 0;
}


/*
run:

a = 1, b = 899
a = 29, b = 31
a = 31, b = 29
a = 899, b = 1

*/

 

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