How to calculate all the less than 500 additive prime numbers in C++

1 Answer

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// Additive primes: primes whose sum of digits is also prime

#include <iostream>
#include <iomanip>

// Check if a number is prime
bool isPrime(unsigned int n) {
    if (n < 2)
        return false;
    if (n % 2 == 0)
        return n == 2;
    if (n % 3 == 0)
        return n == 3;

    for (unsigned int i = 5; i * i <= n; i += 4) {
        if (n % i == 0)
            return false;
        i += 2;
        if (n % i == 0)
            return false;
    }
    return true;
}

// Compute the sum of digits of a number
unsigned int sumDigits(unsigned int n) {
    unsigned int sum = 0;
    while (n > 0) {
        sum += n % 10;
        n /= 10;
    }
    return sum;
}

// Check if a number is an additive prime
bool isAdditivePrime(unsigned int n) {
    return isPrime(n) && isPrime(sumDigits(n));
}

int main() {
    constexpr unsigned int top = 500;

    std::size_t count = 0;

    for (unsigned int i = 1; i < top; i++) {
        if (isAdditivePrime(i)) {
            std::cout << std::setw(3) << i;
            if (++count % 10 == 0)
                std::cout << '\n';
            else
                std::cout << ' ';
        }
    }

    std::cout << "\n\nTotal additive primes = " << count;
}



/*
run:

  2   3   5   7  11  23  29  41  43  47
 61  67  83  89 101 113 131 137 139 151
157 173 179 191 193 197 199 223 227 229
241 263 269 281 283 311 313 317 331 337
353 359 373 379 397 401 409 421 443 449
461 463 467 487

Total additive primes = 54

*/

 



answered May 4 by avibootz
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