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How to define an exabyte constant in Java

1 Answer

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public class ExabyteExample {

    /**
        Java's long type is a signed 64‑bit integer.
        Maximum value: 9,223,372,036,854,775,807 (~9.22 × 10^18)

        Exabyte sizes:

            1 EiB = 2^60  = 1,152,921,504,606,846,976 bytes
            1 EB  = 10^18 = 1,000,000,000,000,000,000 bytes

        Both values fit safely inside a long.
    */

    // Binary exabyte (exbibyte), using a bit shift.
    // 1L << 60 = 2^60 bytes.
    public static final long EXABYTE_EIB = 1L << 60;

    // Decimal exabyte (SI), using a readable numeric literal.
    public static final long EXABYTE_EB = 1_000_000_000_000_000_000L;

    public static void main(String[] args) {
        System.out.println("1 EiB = " + EXABYTE_EIB + " bytes");
        System.out.println("1 EB  = " + EXABYTE_EB  + " bytes");
    }
}



/*
run:

1 EiB = 1152921504606846976 bytes
1 EB  = 1000000000000000000 bytes

*/

 



answered May 3 by avibootz
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