How to write 6 different functions that accept 5 or 7 and return the other number, without using if,switch in TypeScript

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/*
    Six different functions that accept 5 or 7
    and return the other number, without using if/switch.
*/

// 1. Arithmetic sum trick: 5 + 7 = 12
function flipSum(x: number): number {
    return 12 - x;
}

// 2. Product trick: 5 * 7 = 35
function flipProduct(x: number): number {
    return 35 / x;
}

// 3. XOR trick: 5 ^ 7 = 2
//    x ^ 2 flips 5 ↔ 7
function flipXor(x: number): number {
    return x ^ 2;
}

// 4. Modulo-based trick using divisibility:
//    x % 7 === 0 → x is 7
//    x % 5 === 0 → x is 5
//    Boolean → number via Number()
function flipMod(x: number): number {
    return 5 * Number(x % 7 === 0)
         + 7 * Number(x % 5 === 0);
}

// 5. Absolute-value trick: |x - 12| flips 5 ↔ 7
function flipAbs(x: number): number {
    return Math.abs(x - 12);
}

// 6. Array lookup using arithmetic index:
//    For x = 5 → (5 - 5) / 2 = 0 → table[0] = 7
//    For x = 7 → (7 - 5) / 2 = 1 → table[1] = 5
function flipArray(x: number): number {
    const table: number[] = [7, 5];
    const index: number = (x - 5) / 2;
    return table[index];
}

// --- Test functions ---

console.log("flip_sum(5) =", flipSum(5));
console.log("flip_sum(7) =", flipSum(7));
console.log();

console.log("flip_product(5) =", flipProduct(5));
console.log("flip_product(7) =", flipProduct(7));
console.log();

console.log("flip_xor(5) =", flipXor(5));
console.log("flip_xor(7) =", flipXor(7));
console.log();

console.log("flip_mod(5) =", flipMod(5));
console.log("flip_mod(7) =", flipMod(7));
console.log();

console.log("flip_abs(5) =", flipAbs(5));
console.log("flip_abs(7) =", flipAbs(7));
console.log();

console.log("flip_array(5) =", flipArray(5));
console.log("flip_array(7) =", flipArray(7));



/*
OUTPUT:

flip_sum(5) = 7
flip_sum(7) = 5

flip_product(5) = 7
flip_product(7) = 5

flip_xor(5) = 7
flip_xor(7) = 5

flip_mod(5) = 7
flip_mod(7) = 5

flip_abs(5) = 7
flip_abs(7) = 5

flip_array(5) = 7
flip_array(7) = 5

*/

 



answered Apr 1 by avibootz

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