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How to find the shortest identical consecutive subarray in an array with C

1 Answer

0 votes
#include <stdio.h>
#include <stdlib.h>

int* shortest_identical_consecutive_subarray(int arr[], int size, int* outLen) {
    if (size == 0) {
        *outLen = 0;
        return NULL;
    }

    int bestStart = 0;
    int bestLen = size;

    int currentStart = 0;
    int currentLen = 1;

    for (int i = 1; i < size; i++) {
        if (arr[i] == arr[i - 1]) {
            currentLen++;
        } else {
            if (currentLen < bestLen) {
                bestLen = currentLen;
                bestStart = currentStart;
            }
            currentStart = i;
            currentLen = 1;
        }
    }

    if (currentLen < bestLen) {
        bestLen = currentLen;
        bestStart = currentStart;
    }

    int* result = malloc(bestLen * sizeof(int));
    for (int i = 0; i < bestLen; i++)
        result[i] = arr[bestStart + i];

    *outLen = bestLen;
    
    return result;
}

/* ============================================================
   MAIN PROGRAM
   ============================================================ */

int main() {
    int arr[] = {3,3,3, 7,7,7,7,7, 2,2, 5,5,5,5, 9,9,9,9,9,9};
    int size = sizeof(arr) / sizeof(arr[0]);

    int outLen;

    int* resultArr = shortest_identical_consecutive_subarray(arr, size, &outLen);
    printf("Array result: ");
    for (int i = 0; i < outLen; i++) printf("%d ", resultArr[i]);
    printf("\n");
    free(resultArr);

    return 0;
}



/*
run:

Array result: 2 2 

*/

 



answered 19 hours ago by avibootz
edited 18 hours ago by avibootz

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