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How to find the shortest identical consecutive subarray in an array with C++

1 Answer

0 votes
#include <iostream>
#include <vector>

std::vector<int> shortest_identical_consecutive_subvector(const std::vector<int>& vec) {
    if (vec.empty()) return {};

    int bestStart = 0, bestLen = vec.size();  
    int currentStart = 0, currentLen = 1;

    for (int i = 1; i < vec.size(); i++) {
        if (vec[i] == vec[i - 1]) {
            currentLen++;
        } else {
            // End of a run — check if it's the shortest
            if (currentLen < bestLen) {
                bestLen = currentLen;
                bestStart = currentStart;
            }
            currentStart = i;
            currentLen = 1;
        }
    }

    // Check the final run
    if (currentLen < bestLen) {
        bestLen = currentLen;
        bestStart = currentStart;
    }

    return std::vector<int>(vec.begin() + bestStart, vec.begin() + bestStart + bestLen);
}

int main() {
    std::vector<int> vec = {3,3,3, 7,7,7,7,7, 2,2, 5,5,5,5, 9,9,9,9,9,9};

    std::vector<int> result = shortest_identical_consecutive_subvector(vec);

    std::cout << "Shortest identical consecutive subarray: ";
    for (int x : result) std::cout << x << " ";
    std::cout << std::endl;

    return 0;
}



/*
run:
 
Shortest identical consecutive subarray: 2 2 
 
*/

 



answered 4 hours ago by avibootz
edited 3 hours ago by avibootz
...