Question

How to calculate the percentage similarity of two lists in Python

Answer 1

def similarity_based_on_exact_position(lst1, lst2):
    matches = sum(x == y for x, y in zip(lst1, lst2))
     
    return matches / max(len(lst1), len(lst2)) * 100
 
lst1 = [1, 2, 3]
lst2 = [1, 4, 3]
 
print("{:.2f}%".format(similarity_based_on_exact_position(lst1, lst2)))
 
 
  
'''
run:
  
66.67%
 
'''

 

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Answer 2

def similarity_based_on_intersection_items(lst1, lst2):
    intersected_items = set(lst1).intersection(lst2)

    similarity_percentage = (len(intersected_items) / ((len(lst1) + len(lst2)) / 2)) * 100
    
    return similarity_percentage

lst1 = [1, 2, 3]
lst2 = [1, 4, 3]

print("{:.2f}%".format(similarity_based_on_intersection_items(lst1, lst2)))


 
'''
run:
 
66.67%

'''

 

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Answer 3

from difflib import SequenceMatcher

def similarity_fuzzy(lst1, lst2):
    return SequenceMatcher(None, lst1, lst2).ratio() * 100


lst1 = ["abc","xzz", "rws"]
lst2 = ["abc","yzz", "rwq"]

print("{:.2f}%".format((similarity_fuzzy(lst1, lst2))))


  
'''
run:
  
33.33%
 
'''

 

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