Question

How to generate a random color in RGB format with Kotlin

Answer 1

import kotlin.random.Random

fun generateRandomRGBColor() {
    val red = Random.nextInt(0, 256)
    val green = Random.nextInt(0, 256)
    val blue = Random.nextInt(0, 256)

    println("Random RGB Color: rgb($red, $green, $blue)")
}

fun main() {
    generateRandomRGBColor()
}



/*
run:

Random RGB Color: rgb(143, 3, 178)

*/

 

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Answer 2

/*
    Generate a random color in RGB format: rgb(R, G, B)
    This program demonstrates how numbers and bits are used
    to produce valid 8‑bit channel values.
*/

import kotlin.random.Random

// Create a random 8‑bit integer (0–255).
// Random.nextInt(256) returns a value in [0, 256),
// giving exactly one byte of color data.
fun randomChannel(): Int {
    // 8 bits → values from 0 to 255
    return Random.nextInt(256)
}

// Produce a random RGB color by combining the channels.
fun generateRandomRGB(): Triple<Int, Int, String> {
    val r = randomChannel()   // Red channel (8 bits)
    val g = randomChannel()   // Green channel (8 bits)
    val b = randomChannel()   // Blue channel (8 bits)

    // Construct the CSS-style RGB string
    val rgb = "rgb($r, $g, $b)"

    return Triple(r, g, rgb)
}

fun main() {
    val (r, g, rgb) = generateRandomRGB()

    println("Red (8 bits): $r")
    println("Green (8 bits): $g")
    println("Blue (8 bits): ${rgb.substringAfterLast(", ").removeSuffix(")")}")
    println("RGB color: $rgb")
}


/*
run:

Red (8 bits): 143
Green (8 bits): 23
Blue (8 bits): 188
RGB color: rgb(143, 23, 188)

*/

 

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