Question

How to check if a number is lead number (sum of even digits is equal to the sum of odd digits) in C++

Answer 1

#include <iostream>

bool isLeadNumber(int num) {
    int evenSum = 0, oddSum = 0;

    while (num > 0) {
        int digit = num % 10; // Extract the last digit
        if (digit % 2 == 0) {
            evenSum += digit; // Add to even sum if digit is even
        } else {
            oddSum += digit;  // Add to odd sum if digit is odd
        }
        num /= 10; // Remove the last digit
    }

    return evenSum == oddSum; // Check if sums are equal
}

int main() {
    int number = 615341;

    if (isLeadNumber(number)) {
        std::cout << number << " is a lead number." << std::endl;
    } else {
        std::cout << number << " is not a lead number." << std::endl;
    }
}


/*
run:

615341 is a lead number.

*/

 

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