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How to sort the part of an array in Go

1 Answer

0 votes
package main

import (
    "fmt"
    "sort"
)

func main() {
    // Declare a fixed-size array of 9 integers
    var arr = [9]int{15, 6, 19, 8, 3, 7, 9, 1, 4}

    formindex := 2;
    toindex := 5;
    // Extract the portion from index 2 to 6 (inclusive)
    subSlice := make([]int, toindex)
    for i := 0; i < toindex; i++ {
        subSlice[i] = arr[i + formindex]
    }

    // Sort the sub-slice
    sort.Ints(subSlice)

    // Copy the sorted values back into the array
    for i := 0; i < toindex; i++ {
        arr[i + formindex] = subSlice[i]
    }

    fmt.Println(arr)
}


/*
run:
 
[15 6 3 7 8 9 19 1 4]
 
*/

 



answered Aug 12, 2025 by avibootz
edited Aug 12, 2025 by avibootz
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