Welcome to collectivesolver - Programming & Software Q&A with code examples. A website with trusted programming answers. All programs are tested and work.

Contact: aviboots(AT)netvision.net.il

Buy a domain name - Register cheap domain names from $0.99 - Namecheap

Scalable Hosting That Grows With You

Secure & Reliable Web Hosting, Free Domain, Free SSL, 1-Click WordPress Install, Expert 24/7 Support

Semrush - keyword research tool

Boost your online presence with premium web hosting and servers

Disclosure: My content contains affiliate links.

39,844 questions

51,765 answers

573 users

How to declare a function argument that can accept any type in Scala

1 Answer

0 votes
object Main {
  def acceptAnyType(x: Any): Unit = x match {
    case v: Int     => println(s"int: $v")
    case v: Double  => println(s"float: $v")
    case v: String  => println(s"string: $v")
    case v: Boolean => println(s"bool: $v")
    case v: Char    => println(s"char: $v")
    case _          => println("unknown type")
  }

  def main(args: Array[String]): Unit = {
    acceptAnyType(246)
    acceptAnyType(3.14)
    acceptAnyType("ABCD")
    acceptAnyType(true)
    acceptAnyType('A')
  }
}



/*
run:
 
int: 246
float: 3.14
string: ABCD
bool: true
char: A
 
*/
 

 



answered Aug 1, 2025 by avibootz
...