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How to generate an n x n matrix filled with elements from 1 to N^2 in spiral order in C

1 Answer

0 votes
#include <stdio.h>
#include <stdlib.h>

int** generateSpiralMatrix(int n) {
    int** matrix = malloc(n * sizeof(int*));
    for (int i = 0; i < n; i++) {
        matrix[i] = malloc(n * sizeof(int));
    }

    int top = 0, bottom = n - 1;
    int left = 0, right = n - 1;
    int num = 1;

    while (top <= bottom && left <= right) {
        // Fill top row
        for (int i = left; i <= right; ++i)
            matrix[top][i] = num++;
        top++;

        // Fill right column
        for (int i = top; i <= bottom; ++i)
            matrix[i][right] = num++;
        right--;

        // Fill bottom row
        if (top <= bottom) {
            for (int i = right; i >= left; --i)
                matrix[bottom][i] = num++;
            bottom--;
        }

        // Fill left column
        if (left <= right) {
            for (int i = bottom; i >= top; --i)
                matrix[i][left] = num++;
            left++;
        }
    }

    return matrix;
}

void freeMatrix(int** matrix, int n) {
    for (int i = 0; i < n; i++)
        free(matrix[i]);
    free(matrix);
}

int main() {
    int n = 3; // size of the matrix
    int** spiralMatrix = generateSpiralMatrix(n);

    for (int i = 0; i < n; i++) {
        for (int j = 0; j < n; j++) {
            printf("%d\t", spiralMatrix[i][j]);
        }
        printf("\n");
    }

    freeMatrix(spiralMatrix, n);
    
    return 0;
}



/*
run:

1	2	3	
8	9	4	
7	6	5

*/



 



answered Jun 24, 2025 by avibootz
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