Question

How to match the first word after an expression in a string using RegEx with Go

Answer 1

package main

import (
    "fmt"
    "regexp"
)

func findNextWord(text, expression string) {
    // Escape special characters if needed — simplified for "fox" style cases
    pattern := regexp.MustCompile(expression + `\s+(\w+)`)
    match := pattern.FindStringSubmatch(text)

    if len(match) > 1 {
        fmt.Printf("The first word after '%s' is: %s\n", expression, match[1])
    } else {
        fmt.Println("No match found!")
    }
}

func main() {
    text := "The quick brown fox jumps over the lazy dog."
    expression := "fox"

    findNextWord(text, expression)
}



/*
run:

The first word after 'fox' is: jumps

*/

 

70+ SQL courses for beginners and professionals