Question

How to use the hypot() to get the square root of the sum of squares of its arguments in Java

Answer 1

package javaapplication1;

public class JavaApplication1 {
 
    public static void main(String[] args) {
        
        System.out.println("Math.hypot(3, 4) = " + Math.hypot(3, 4));
        System.out.println("Math.sqrt(3*3 + 4*4) = " + Math.sqrt(3*3 + 4*4));
        System.out.println("Math.hypot(1, 1) = " + Math.hypot(1, 1));
        System.out.println("Math.hypot(-9, -25) = " + Math.hypot(-9, -25));
        System.out.println("Math.hypot('3', '4') = " + Math.hypot('3', '4'));
    }
}
 
/*
run:

Math.hypot(3, 4) = 5.0
Math.sqrt(3*3 + 4*4) = 5.0
Math.hypot(1, 1) = 1.4142135623730951
Math.hypot(-9, -25) = 26.570660511172846
Math.hypot('3', '4') = 72.83543093852057
 
*/

 

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