Question

How to break the outer loop in C

Answer 1

#include <stdio.h>
 
int main(void)
{
    for (int i = 0; i < 6; i++) {
        printf("i)%d ", i);
    	for (int j = 0; j < 4; j++) {
    	    printf(" j)%d ", j);
    		if (i == 4) {
    			goto end;
    		}
    	}
    	printf("\n");  			
    }
    end:
 
    return 0;
}
  
  
  
/*
run:
  
i)0  j)0  j)1  j)2  j)3 
i)1  j)0  j)1  j)2  j)3 
i)2  j)0  j)1  j)2  j)3 
i)3  j)0  j)1  j)2  j)3 
i)4  j)0 
  
*/

 

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Answer 2

#include <stdio.h>

int main() {
    int flag = 0;
    
    for (int i = 0; i < 6 && !flag; i++) {
        for (int j = 0; j < 4; j++) {
            if (i == 3) {
                flag = 1;
                break;
            }
            printf("i = %d, j = %d\n", i, j);
        }
    }
    
    return 0;
}

  
  
/*
run:
  
i = 0, j = 0
i = 0, j = 1
i = 0, j = 2
i = 0, j = 3
i = 1, j = 0
i = 1, j = 1
i = 1, j = 2
i = 1, j = 3
i = 2, j = 0
i = 2, j = 1
i = 2, j = 2
i = 2, j = 3
  
*/

 

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Answer 3

#include <stdio.h>

void nestedLoops() {
    for (int i = 0; i < 6; i++) {
        for (int j = 0; j < 4; j++) {
            if (i == 3) {
                return;
            }
            printf("i = %d, j = %d\n", i, j);
        }
    }
}

int main() {
    nestedLoops();

    return 0;
}


  
  
/*
run:
  
i = 0, j = 0
i = 0, j = 1
i = 0, j = 2
i = 0, j = 3
i = 1, j = 0
i = 1, j = 1
i = 1, j = 2
i = 1, j = 3
i = 2, j = 0
i = 2, j = 1
i = 2, j = 2
i = 2, j = 3
  
*/

 

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