How to write a recursive function that counts digits of a number in Swift

1 Answer

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func countDigits(_ number: Int) -> Int {
    // Base case: If the number is 0, return 0
    if number == 0 {
        return 0
    }
    // Recursive case: Divide the number by 10 and count recursively
    return 1 + countDigits(number / 10)
}

let num = 78902

print("Number of digits in \(num) is: \(countDigits(num))") 



/*
run:

Number of digits in 78902 is: 5

*/

 



answered Apr 8, 2025 by avibootz
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