Question

How to extract the unique integers from a list excluding duplicates in Kotlin

Answer 1

fun getUniqueExcludeDuplicates(lst: List<Int>): List<Int> {
    // Map to count occurrences of each number
    val frequency = mutableMapOf<Int, Int>()

    // Count frequencies of each number in the list
    for (num in lst) {
        frequency[num] = frequency.getOrDefault(num, 0) + 1
    }

    // Collect numbers that appear only once
    return lst.filter { num -> frequency[num] == 1 }
}

fun main() {
    val lst = listOf(1, 2, 3, 5, 8, 3, 1, 1, 0, 6, 5, 7, 3, 1, 4, 9)

    val uniqueValues = getUniqueExcludeDuplicates(lst)

    println("Unique values (excluding duplicates): ${uniqueValues.joinToString(" ")}")
}
 
   
      
/*
run:
   
Unique values (excluding duplicates): 2 8 0 6 7 4 9
  
*/

 

70+ SQL courses for beginners and professionals