Question

How to sort each row from a two-dimensional array in Rust

Answer 1

fn main() {
    let mut arr2d = [
        [3, 1, 2, 0],
        [9, 7, 8, 4],
        [6, 5, 4, 1],
    ];

    for row in arr2d.iter_mut() {
        row.sort();
    }

    for row in &arr2d {
        println!("{:?}", row);
    }
}

 
      
/*
run:
   
[0, 1, 2, 3]
[4, 7, 8, 9]
[1, 4, 5, 6]
     
*/

 

70+ SQL courses for beginners and professionals