How to create an array from a 2D array that only includes the non-zero elements in C++

1 Answer

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#include <iostream>
#include <vector>

int main() {
    int array[3][4] = {
        {1, 0, 8, 2},
        {0, 7, 3, 0},
        {9, 0, 0, 4}
    };

    std::vector<int> nonZeroList;

    // Collect non-zero elements
    for (int i = 0; i < 3; ++i) {
        for (int j = 0; j < 4; ++j) {
            if (array[i][j] != 0) {
                nonZeroList.push_back(array[i][j]);
            }
        }
    }

    // Convert the list back to a one-dimensional array
    int* resultArray = new int[nonZeroList.size()];
    for (size_t i = 0; i < nonZeroList.size(); ++i) {
        resultArray[i] = nonZeroList[i];
    }

    for (size_t i = 0; i < nonZeroList.size(); ++i) {
        std::cout << resultArray[i] << " ";
    }
    std::cout << std::endl; 

    delete[] resultArray; // Release the dynamically allocated memory
}



/*
run:

1 8 2 7 3 9 4 

*/

 



answered Feb 13, 2025 by avibootz
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