Question

How to find the min and max of an int array in JavaScript

Answer 1

const array = [3, 14, 4, 1, 5, 90, 2, 6, 89, 3, 7];

const min = Math.min(...array);
const max = Math.max(...array);

console.log(`Minimum: ${min}`);
console.log(`Maximum: ${max}`);



/*
run:

Minimum: 1
Maximum: 90

*/

 

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Answer 2

const array = [3, 14, 4, 1, 5, 90, 2, 6, 89, 3, 7];

let min = array[0];
let max = array[0];

const size = array.length;

for (let i = 1; i < size; i++) {
    if (array[i] < min) {
        min = array[i];
    }
    if (array[i] > max) {
        max = array[i];
    }
}

console.log(`Minimum: ${min}`);
console.log(`Maximum: ${max}`);



/*
run:

Minimum: 1
Maximum: 90

*/

 

70+ SQL courses for beginners and professionals

Answer 3

const array = [3, 14, 4, 1, 5, 90, 2, 6, 89, 3, 7];

const min = array.reduce((a, b) => Math.min(a, b));
const max = array.reduce((a, b) => Math.max(a, b));

console.log(`Minimum: ${min}`);
console.log(`Maximum: ${max}`);



/*
run:

Minimum: 1
Maximum: 90

*/

 

70+ SQL courses for beginners and professionals