How to count the digits before and after the decimal point in C

1 Answer

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#include <stdio.h>
#include <math.h>
#include <string.h>

void removeTrailingZeros(char *str) {
    int len = strlen(str);
    
    while (len > 0 && str[len - 1] == '0') {
        str[len - 1] = '\0';
        len--;
    }
}

int main() {
    char s[32];
    double d = 345912.8036;
    int left, right;
  
    sprintf(s, "%f", d);
    removeTrailingZeros(s);
  
    sscanf(s, "%d.%d", &left, &right);
 
    printf("Total left digits: %d\n\r", (int)log10(left) + 1);
    printf("Total right digits: %d\n\r", (int)log10(right) + 1);
      
    return 0;
}
  
  
  
/*
run:
  
Total left digits: 6
Total right digits: 4
  
*/

 



answered Nov 13, 2024 by avibootz
edited Nov 13, 2024 by avibootz

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