Question

How to split an array into evenly sized chunks in Go

Answer 1

package main

import "fmt"

func chunkSlice(slice []int, chunkSize int) [][]int {
    var chunks [][]int
    var size = len(slice)
    
    for i := 0; i < size; i += chunkSize {
        end := i + chunkSize
        if end > len(slice) {
            end = len(slice)
        }
        chunks = append(chunks, slice[i:end])
    }
    
    return chunks
}

func main() {
    arr := []int{1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14}
    chunkSize := 3
    
    chunks := chunkSlice(arr, chunkSize)
    
    fmt.Println(chunks)
    
    fmt.Println(chunks[0])
    
    fmt.Println(chunks[0][0])
    fmt.Println(chunks[0][1])
    fmt.Println(chunks[0][2])
}

 
 
/*
run:
 
[[1 2 3] [4 5 6] [7 8 9] [10 11 12] [13 14]]
[1 2 3]
1
2
3

*/

 

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