Welcome to collectivesolver - Programming & Software Q&A with code examples. A website with trusted programming answers. All programs are tested and work.

Contact: aviboots(AT)netvision.net.il

Buy a domain name - Register cheap domain names from $0.99 - Namecheap

Scalable Hosting That Grows With You

Secure & Reliable Web Hosting, Free Domain, Free SSL, 1-Click WordPress Install, Expert 24/7 Support

Semrush - keyword research tool

Boost your online presence with premium web hosting and servers

Disclosure: My content contains affiliate links.

39,872 questions

51,795 answers

573 users

How to find the sum of each row and each column of a matrix (2D array) in Rust

1 Answer

0 votes
fn main() {
    let arr: [[i32; 4]; 3] = [
        [1, 2, 3, 5],
        [4, 5, 6, 5],
        [7, 8, 9, 5],
    ];

    let rows = arr.len();
    let cols = arr[0].len();

    for i in 0..rows {
        let sum_row: i32 = arr[i].iter().sum();
        println!("Sum of row: {} = {}", i, sum_row);
    }

    for i in 0..cols {
        let sum_col: i32 = (0..rows).map(|j| arr[j][i]).sum();
        println!("Sum of col: {} = {}", i, sum_col);
    }
}




/*
run:
  
Sum of row: 0 = 11
Sum of row: 1 = 20
Sum of row: 2 = 29
Sum of col: 0 = 12
Sum of col: 1 = 15
Sum of col: 2 = 18
Sum of col: 3 = 15
  
*/

 



answered Nov 3, 2024 by avibootz
...